A javalina rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel?

A javalina rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure below). He has 580 feet of fencing available to complete the job. What is the largest possible total area of the four pens?|||2y + 5x = 580


A = xy = x(290-(5/2)x) = 290x - (5/2)x虏


A' = 290 - 5x


let A' = 0, then x = 58 ft and y = 145 ft or area= 8410 ft虏