A farmer wishes to put a fence around a rectangular field and then divide the field into five rectangular plots by placing four fences parallel to one of the sides. If the farmer can afford only 3000 yards of fencing, what dimensions will give the maximum rectangular area?|||ur two equations are-
6w + 2l = 3000 --%26gt; l=1500-3w
max = w x l
max= w(1500-3w)
=-3w^2 + 1500w
=-3(w^2 - 500w)
=-3(w^2 - 500w + 62500 - 62500)
=-3(w^2 -500w +62500) + 187,500
=-3(w - 250) ^2 +187,500
therefore, ur maximum occurs when w=250, and is equal to187,500
l=1500 - 3(250)
l=750|||calculus and differentiation, i'm sure
i might be back with the working, but i can't see any paper around
i shall search
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