What are the dimensions, in feet, for a rectangular garden that will use exactly 80 feet of fencing?

Mr. James wants to plant a garden that would be in the shape of a rectangle. He was given 80 feet of fencing to enclose his garden. He want the length to be 10 more than twice the width.





What are the dimensions, in feet, for a rectangular garden that will use exactly 80 feet of fencing?





Please explain your answer!|||L = (2W +10)


so 2(2W + 10) + 2W = 80


6W + 20 = 80


6W = (80 - 20)


W = 10ft L = 30ft.|||do you own homework|||We know:


Perimeter will be the amount of fencing, 80 feet.


Perimeter of rectangle is one side + one side + one side + one side.


A rectangle has two sides the same (length) and two other sides the same (width).


Formula to use is 2x + 2y = 80 (x = length, y = width)


Length is supposed to be +10 than 2 times width. This can be written as x = 2y + 10





Now we can substitute x into first formula:


2x + 2y = 80; x = 2y + 10


2(2y+10) + 2y = 80


4y + 20 + 2y = 80


6y + 20 = 80


6y = 80-20


6y = 60


y = 60/6


y = 10





To find x (length) we place 10 into formula x = 2y + 10:


x = 2(10) + 10


x = 20 + 10


x = 30





Dimensions of rectangle are 10, 30,10, 30 (10 is width and 30 is length)