A pig rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure below). He has 590 feet of fencing available to complete the job. What is the largest possible total area of the four pens?|||Let the width be x.
Then the length will be (590 - 5x)/2.
A = x(590 - 5x)/2
A = 295x - (5/2)x^2
dA/dx = 295 - 5x = 0
5x = 295
x = 59ft
A = 59(590 - 5(59))/2
A = 8702.5 ft^2
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